Ln(x)^(-1/2)

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Solution for Ln(x)^(-1/2) equation: 


D( x )

ln(x) < 0

x <= 0

ln(x) = 0

ln(x) < 0

ln(x) < 0

ln(x)+0 < 0 // - 0

ln(x) < 0

ln(x) in (-oo:0)

ln(x) < ln(e^0)

x < e^0

x < 1

x <= 0

ln(x) = 0

ln(x) = 0

ln(x) = ln(e^0)

x = e^0

x = 1

x in (1:+oo)

(ln(x))^(-1/2) = 0

t_1 = ln(x)

1*t_1^(-1/2) = 0 // : 1

t_1^(-1/2) = 0

t_1 należy do O

x belongs to the empty set

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